A
amymon87
Member
Can someone help me with the difference in calculations between calculating (qx)^d.
In Q13 - the independent rate of mort is given as 110% AM92 and so qx in the examiner's report is calculated as 1.1*qx from tables. What is the calculation then used for (qx)^d?
In Q14 - mortality is 90% AM92 and so qx is directly from tables but then (qx)^d is 0.9*qx
I'm sure I'm missing a link but cannot seem to work it out - I know you can calculate mu in q 13 and then get (qx)^d but this doesn't seem to work either and seems like too much work for just 3 marks.
Thanks
In Q13 - the independent rate of mort is given as 110% AM92 and so qx in the examiner's report is calculated as 1.1*qx from tables. What is the calculation then used for (qx)^d?
In Q14 - mortality is 90% AM92 and so qx is directly from tables but then (qx)^d is 0.9*qx
I'm sure I'm missing a link but cannot seem to work it out - I know you can calculate mu in q 13 and then get (qx)^d but this doesn't seem to work either and seems like too much work for just 3 marks.
Thanks