Sept 2014 Q13/Q14 qx

Discussion in 'CT5' started by amymon87, Apr 3, 2016.

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  1. amymon87

    amymon87 Member

    Can someone help me with the difference in calculations between calculating (qx)^d.
    In Q13 - the independent rate of mort is given as 110% AM92 and so qx in the examiner's report is calculated as 1.1*qx from tables. What is the calculation then used for (qx)^d?
    In Q14 - mortality is 90% AM92 and so qx is directly from tables but then (qx)^d is 0.9*qx

    I'm sure I'm missing a link but cannot seem to work it out - I know you can calculate mu in q 13 and then get (qx)^d but this doesn't seem to work either and seems like too much work for just 3 marks.

    Thanks
     
  2. Hemant Rupani

    Hemant Rupani Senior Member

  3. amymon87

    amymon87 Member

    OK - so that part of the question is not applicable anymore. I figured it was something to do with the change.

    I have read the update but I'm still not sure on what the exact differences are in the syllabus' are. Is it fair to say that where they mention calculating dependent rates from independent rates is now not applicable. Is there anything else that is easily recognised as now not on the syllabus?
     
  4. Hemant Rupani

    Hemant Rupani Senior Member

    Yes. Thiele's differential equation.
     
  5. amymon87

    amymon87 Member

    Thanks!
     

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