X4.11 Question

Discussion in 'CT3' started by asmkdas, Apr 7, 2013.

  1. asmkdas

    asmkdas Member

    My problem is in question X2.11's solution

    In (i) they have done it as Let X be the number of squares moved up the drain pipe each turn. Hence:

    X : -1 0 +1 +2
    Probability : 1/6 5/12 1/3 1/12

    My problem is how they got those probabilities. I have understood rest of the problem.

    Thanks in advance.
     
  2. suraj

    suraj Member



    Just draw the sample space of the outcomes of roll of two dice

    (1,1),(1,2)........
    (2,1),(2,2).......
    .
    .
    .
    (6,1),(6,2)......(6,6)

    and then work out the probabilities.

    for example - 11 can come like this [ (5,6), (6,5) ] and 12 like this (6,6)
    So probability of (+2) movement = 3/36
     
  3. asmkdas

    asmkdas Member

    I was calculating outcome of 11 and 12 as (5,6),(6,5) and (6,6),(6,6) respectively. And my probabilities were coming out as 4/36.
    My mistake. Thanks for the kind help.
     

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