X2 Assignment Q2.3

Discussion in 'CT6' started by mcallist, Mar 5, 2017.

  1. mcallist

    mcallist Member

    Hi all,

    Stupid question I'm sure but could someone please explain this.

    When we take the lambda and the mu outside of the brackets, the negative 1 is only subtracted away from the MY(t) and not the MX(t) like it was in the line above.
    Could someone please explain the step in between?

    Thanks a lot,
    Tom
     
    mcallist, Mar 5, 2017
    #1
  2. Bharti Singla

    Bharti Singla Senior Member

    They have taken lemda+mu outside. If you see it by again taking (lemda+mu) inside, you will get:
    exp{[Lemda×Mx(t) + mu×My(t) - Lemda -mu]}
    Same expression as above.
    Moreover, see the formula attached below in the pic.
     

    Attached Files:

    Last edited: Mar 5, 2017
    Bharti Singla, Mar 5, 2017
    #2
    John Lee and mcallist like this.
  3. mcallist

    mcallist Member

    Hi Bharti,
    Thanks very much, that's great. :)
    Tom
     
    mcallist, Mar 6, 2017
    #3
  4. Bharti Singla

    Bharti Singla Senior Member

    Your welcome! :)
     
    Bharti Singla, Mar 6, 2017
    #4

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