Can someone please help me solving this sum? (What are the probable outcomes when 4 coins are thrown? Here i can not use 16 outcomes as coin is biased or unbiased that is not known). Please help.
When 4 coins are tossed, we can get 0,1,2,3 or 4 heads. Acceptance of null hypothesis is at 1,2 and 3 heads, so rejection at 0 and 4 heads.
Ok. I tried with that. In that case type I error = (probability of rejecting H0| H0 is true) = 2/5 * 0.5 = 0.2 but the given answer is 0.125
