Not as fare as yourself, so I'll attempt q2 about ch5.
thats from defn of tPx = l_(x+t) / l_(x)
when you take logs this becomes ln l_(x+t) - l_x
And as in this case we have
l_(x+n) - l_(x+t)
where the first l_(x+n) is constant with respect to t therefore differentiating removes this left with mu_(x+t)
hope this helps.
Last edited by a moderator: Dec 28, 2006