"20v^3.5 + 18v^6 = 24.4875 = Pv^4 + Qv^7 (equating PVs) (1)
111.1077 = 4Pv^4 + 7Qv^7 (2)
Solving (1) and (2) simultaneously gives:
P = 29.431
Q = 8.547"
Hi Guys,
Actually, the solutions in my book for the practice exam question that you have shown above says P = 20,103 and Q = 4,385.
But nevertheless, I'm sorry, I haven't made myself clear. It's just the solving of the simultaneous equations bit that I am having trouble with.
What were the steps you used to solve for P and Q from equations (1) and (2)?
The other example (from p29) would be to solve for P and Q again, the following:
Pv^5 + Qv^10 = 62,418
5Pv^6 + 100Qv11 = 404,398
I tried to solve but my answers were about $1000 out which doesn't seem close enough. Not sure if its rounding errors or what. That's why I want to see what process other people use.
Cheers
Last edited by a moderator: Feb 1, 2011