Darragh Kelly
Ton up Member
Hi,
I've been looking at method 1 of the examiners solution to this question. So they differentiate B(t)=F(t)-E(t) w.r.t vega. But they say that the vega of a bond is unknown. However the black-scholes framework is being applied, can we not use the fact that del,F(t)/del,sigma = 0 (as all greeks except for delta are 0 for the share price which in this case is the total firm value F(t)). So then we have del,B(t)/del,sigma = -del,E(t)/del,sigma, and then as E(t) is equivalent to the value of the call option and the vega of a call = S(t)*N'(d1)*(T-t)^0.5 and just replace del,E(t)/del,sigma = F(t)*N'(d1)*(T-t)^0.5. So then finally as minus del,E(t)/del,sigma = del,B(t)/del,sigma, the vega of the bond is just - F(t)*N'(d1)*(T-t)^0.5? I don't get the same answer as the acted solution which looks at it differently...
Thanks,
Darragh
I've been looking at method 1 of the examiners solution to this question. So they differentiate B(t)=F(t)-E(t) w.r.t vega. But they say that the vega of a bond is unknown. However the black-scholes framework is being applied, can we not use the fact that del,F(t)/del,sigma = 0 (as all greeks except for delta are 0 for the share price which in this case is the total firm value F(t)). So then we have del,B(t)/del,sigma = -del,E(t)/del,sigma, and then as E(t) is equivalent to the value of the call option and the vega of a call = S(t)*N'(d1)*(T-t)^0.5 and just replace del,E(t)/del,sigma = F(t)*N'(d1)*(T-t)^0.5. So then finally as minus del,E(t)/del,sigma = del,B(t)/del,sigma, the vega of the bond is just - F(t)*N'(d1)*(T-t)^0.5? I don't get the same answer as the acted solution which looks at it differently...
Thanks,
Darragh