September 2016 q 8 (i)

Discussion in 'CT4' started by Harashima Senju, Sep 21, 2017.

  1. Harashima Senju

    Harashima Senju Ton up Member

    Can you kindly explain how the population on 1 Jan 2014 was derived. I thought you would use linear interpolation but I get the wrong answer using the following workings

    • Population on 1 Jan 2014 = \(2 333 +\frac{2}{12}(\frac{2417 - 2 333}{12}) = 2 334.1666\)
     
  2. Pede

    Pede Member

    I haven't even looked at the question - but why have you got 12 twice in your interpolation? Look at the reasonability of your answer, you want to be 1/6th of the way through the interval, and you're still at the very bottom!
     
  3. Harashima Senju

    Harashima Senju Ton up Member

    I have recalculated it as follows
    • \(\frac{1}{2}(x + 2 333)\frac{2}{12} + \frac{1}{2}(x + 2 417)\frac{10}{12} = \frac{1}{2}(2 333 + 2417)\)
    • x = 1 Jan gives me the correct answer of 2 347
     

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