1. 

   Neetu Verma Member

   In September 2002
   1)- Question 2,
   Solution goes to n*log(.02)<=log(10^-9) to n>=log(10^-9)/log(.02)
   According to me
   .02^n <= 10^-9
   n*log(.02) <= log(10^-9)
   n <= log(10^-9)/log(.02)
   Any one tell me where I make mistake?

    

   Neetu Verma, Apr 7, 2008

   #1
2. 

   Actually Member

   log(.02) is negative so the inequality reverses.
   
   i.e 2 > 1. Divide by -1 gives -2 < -1

    

   Actually, Apr 8, 2008

   #2

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