Sept 2016 q10 (ii)

Discussion in 'CT4' started by Puleng_M, Apr 20, 2018.

  1. Puleng_M

    Puleng_M Member

    The solution calculates the baseline hazard=0.6/exp(-0.035)
    And then takes that baseline hazard and multiplies it with exp(0.15) which is the hazard from the covariate i.e. 0.6*exp(0.15)/exp(-0.035), the solution says this is the probability of the female getting discharged. But isn't this the hazard of being discharged rather than the probability?
     
  2. I also think it should be hazard instead of probability.
     

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