question in april 2006

Discussion in 'CT3' started by Neetu Verma, Mar 30, 2008.

  1. Neetu Verma

    Neetu Verma Member

    1)-Question 13,part(ii)b,in past question paper April 2004
    Anyone tell me ,why, we take p=.8,.6,.4,.2
    2)-question 5,part (ii),in paper March 2006
    In alternative comment,take approximations are quite good for p=.1 But
    approximation is not valid because np<5.So why takes approximations are quite good .
     
    Last edited by a moderator: Apr 4, 2008
  2. 1)-Question 13,part(ii)b,in past question paper April 2004
    Anyone tell me ,why, we take p=.8,.6,.4,.2

    For this I imagined a set of orderd observations
    0 < x1 < x2 < x3 < x4 < infinity

    Since we want each interval to be probability 0.2
    we basically want
    P(0 < X < x1) = 0.2
    P(x1 < X < x2) = 0.2
    P(x2 < X < x3) = 0.2
    P(x3 < X < x4) = 0.2
    P(x4 < X < infinity) = 0.2 or P(X > x4) = 0.2

    Hence
    P(X < x4) = 0.8
    P(X < x3) = 0.6
    P(X < x2) = 0.4
    P(X < x1) = 0.2

    2)-question 5,part (ii),in paper March 2006
    In alternative comment,take approximations are quite good for p=.1 But
    approximation is not valid because np<5.So why takes approximations are quite good .

    I read somewhere that np<5 means that normal approx is not suitable, Poisson is more reliant on small p, N>= 20

    Hope this helps.
    Ed
     
    Last edited by a moderator: Mar 31, 2008
  3. Neetu Verma

    Neetu Verma Member

    Thanks for this help.
     

Share This Page