Qu 3.15

Discussion in 'CT5' started by Sharon, Mar 1, 2006.

  1. Sharon

    Sharon Member

    Can anyone explain the solution to qu 3.15 to me? I understand that q[x]+1 > q[x+1] and q[x+2]+2 > q[x+4] but I don't understand why the difference between the second pair is less than the first.
     
  2. i dunno

    let me try my hand at this one. say we got q[x+s]+s, now this lies somewhere between (qx+2s,...,q[x+2s]),
    now as s->big number:
    q[x+s]+s ->qx+2s i.e it moves towards the left limit
    q[x+2s]->q[x+2s] i.e. it stays at the lower limit
    but then the difference gets bigger!,
    hmm maybe i should just change the question, cause i dont want to change my answer
    looking at q[x+s]+s<q[x]+2s then the difference gets smaller..

    i know i am wrong, because 'the book' is infallible. we may have to use non logical enlightened reasoning, any rousseaux's out there?
     

Share This Page