Q&a3 - Q3.8

Discussion in 'CT8' started by Jesoos, Mar 13, 2014.

  1. Jesoos

    Jesoos Member

    I understand the general points in the solution on how to identify the graphs to the different elements being varied.

    However, for completeness sake I calculated the call option equation to see if I could get the values on the graphs. Unfortunately I do not even come close, am I doing something wrong?

    Take Graph 2 for example. I calculate the call option as follows:

    S - K*exp(-rT)

    1. S=240 => 240 - 250*exp(-0.06*0.5) = -2.6114 but Graph 2 does not even contain a negative value?

    2. S=250 => 250 - 250*exp(-0.06*0.5) = 7.3886 but Graph 2 shows a value between 10 and 20 for S=250.

    I suspect my calculation of the call option might be wrong and I need to include the volatility value of 0.2 somewhere into this calc?

    Please can someone explain what I am doing wrong?

    Thank you!
     

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