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Q&A Bank Q1.25

G

gooneraki

Member
In part (ii)(a),
exp(-ΘM^1/3) / (1 - exp(-ΘM^1/3)) becomes
1 / (exp(ΘM^1/3) -1)

I am not able to do this mathematically :(
 
It's been a long time since I did CT6 but I think you just have to divide the numerator and denominator by exp(-ΘM^1/3).

This is allowed because you are essentially then multiplying by exp(-ΘM^1/3) /exp(-ΘM^1/3) i.e. multiplying by 1.
 
Satya said:
It's been a long time since I did CT6 but I think you just have to divide the numerator and denominator by exp(-ΘM^1/3).

This is allowed because you are essentially then multiplying by exp(-ΘM^1/3) /exp(-ΘM^1/3) i.e. multiplying by 1.
Click to expand...

My god this is embarrassing.
I really forgot my maths.
Thanks, will delete this post..
 
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