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Q/A bank part1

N

Neetu Verma

Member
Q/A bank part 1 Question 1.6 (i)
any one tell me.... How to find values of the table of the loss functions?????
thanks
 
Here is the way

Here the possible values for the parameter 'Theeta' are 1/4, 1/2, 3/4.
So there will be 3X3 combinations between the Actual Parameter and the guessed parameter. If the Actual value is equal to the guessed value, then no loss means no penalty. Thats why we have zeros in the diagonal.

If the values are not matching, then the penalty is given as '200 times the absolute value of the error'.

Absolute value of the error = Modulus(Actualvalue - Guessedvalue).

Take the 1X3(1st row,3rdcol) cell from the table :
Here the Actual value = 1/4, Guessed value=3/4
Absolute value of the error = Mod(1/4 - 3/4) = 2/4
Now 200 times of this error = 200*(2/4) = 100

Repeat the same process for all the cells.

Hope its clear now.

Thanks.
 
nageshmcl said:
Here the possible values for the parameter 'Theeta' are 1/4, 1/2, 3/4.
So there will be 3X3 combinations between the Actual Parameter and the guessed parameter. If the Actual value is equal to the guessed value, then no loss means no penalty. Thats why we have zeros in the diagonal.

If the values are not matching, then the penalty is given as '200 times the absolute value of the error'.

Absolute value of the error = Modulus(Actualvalue - Guessedvalue).

Take the 1X3(1st row,3rdcol) cell from the table :
Here the Actual value = 1/4, Guessed value=3/4
Absolute value of the error = Mod(1/4 - 3/4) = 2/4
Now 200 times of this error = 200*(2/4) = 100

Repeat the same process for all the cells.

Hope its clear now.

Thanks.
Click to expand...
its very clear, thank you very much...
 
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