• We are pleased to announce that the winner of our Feedback Prize Draw for the Winter 2024-25 session and winning £150 of gift vouchers is Zhao Liang Tay. Congratulations to Zhao Liang. If you fancy winning £150 worth of gift vouchers (from a major UK store) for the Summer 2025 exam sitting for just a few minutes of your time throughout the session, please see our website at https://www.acted.co.uk/further-info.html?pat=feedback#feedback-prize for more information on how you can make sure your name is included in the draw at the end of the session.
  • Please be advised that the SP1, SP5 and SP7 X1 deadline is the 14th July and not the 17th June as first stated. Please accept out apologies for any confusion caused.

Q&A Bank 3.27

A

Anjum

Member
An office manager wants to analyse the variability in the time taken for her typists to
complete a given task. She has given seven typists the task and the results are as
follows (in minutes):
15, 17.2, 13.7, 11.2, 18, 15.1, 14
The manager wants a 95% confidence interval for the true standard deviation of time
taken of the form s > k . Calculate the value of k .

As per the solution it is given

upload_2017-1-30_8-56-29.png

doubt is since we want 95% confidence interval for s>k so we need to find only the lower limit of s and should have thus taken chisquare at 0.95 level as (0.975, df) gives the lower value for a 95% confidence interval for s>k then why are we taking chisquare value at 0.05 level.
 
Hi
I guess this is one-sided confidence interval i.e. (k,∞). Means the whole 5% area will be in left in this case. When finding 95% CI using two-sided CI, the 5% region is divided among both sides each of 2.5%. But in this case, the whole region of 5% will be in left side and the upper limit will be ∞. See the graph below, it may help.
 

Attachments

  • Screenshot_2017-01-31-02-20-14_com.android.chrome_1485809442812.jpg
    Screenshot_2017-01-31-02-20-14_com.android.chrome_1485809442812.jpg
    42.4 KB · Views: 4
Back
Top