Q&A Bank 3.11

Discussion in 'CT3' started by Elroy, Jun 30, 2008.

  1. Elroy

    Elroy Member

    Why can't you just use the cdf direclty here?

    ie L(lamda) = P(x<200)^(3)P(x>200)^(47)

    ??

    Thanks.
     
  2. anand sanjay

    anand sanjay Member

    Ans To Q&a Bank3.11

    I Think Question Says Calculate Mle Ofaverage(mu) Instead Of Lambda From .anand Sanjay
     
  3. Elroy

    Elroy Member

    Sorry. I'm still confused as to why my approach is wrong. The model answer finds MLE of lambda and then uses this to calculate mu.

    47 have a lifetime greater than 200 days and 3 less. So why can't we use the CDF of the exponential distibution directly? My approach must be wrong as I get a negative answer, but why?
     
  4. Elroy

    Elroy Member

    oops.. my aproach does work.. must have got my sums wrong!
     

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