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Q&A Bank 3.11

E

Elroy

Member
Why can't you just use the cdf direclty here?

ie L(lamda) = P(x<200)^(3)P(x>200)^(47)

??

Thanks.
 
Ans To Q&a Bank3.11

I Think Question Says Calculate Mle Ofaverage(mu) Instead Of Lambda From .anand Sanjay
 
anand sanjay said:
I Think Question Says Calculate Mle Ofaverage(mu) Instead Of Lambda From .anand Sanjay
Click to expand...

Sorry. I'm still confused as to why my approach is wrong. The model answer finds MLE of lambda and then uses this to calculate mu.

47 have a lifetime greater than 200 days and 3 less. So why can't we use the CDF of the exponential distibution directly? My approach must be wrong as I get a negative answer, but why?
 
Elroy said:
Sorry. I'm still confused as to why my approach is wrong. The model answer finds MLE of lambda and then uses this to calculate mu.

47 have a lifetime greater than 200 days and 3 less. So why can't we use the CDF of the exponential distibution directly? My approach must be wrong as I get a negative answer, but why?
Click to expand...

oops.. my aproach does work.. must have got my sums wrong!
 
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