1. 

   Dikshay Ramnani Member

   In solution 2.7, Convolutions
   Why after substituting t=x/z the upper limit of integration has become 1 in place of z ?
   Also,
   Why only we have substituted t=x/z ?
   
   Thanks in advance.

    

   Dikshay Ramnani, Mar 31, 2015

   #1
2. 

   Hemant Rupani Senior Member

   after substitution lower bound of integration will be t=0/z=0 & upper bound t=z/z=1
   
   

   that is a trick to make it look like Beta Distribution.

    

   Hemant Rupani, Apr 1, 2015

   #2

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