Proof of formula for u & d in Binomial Tree

Discussion in 'SP6' started by JNSamara, Apr 15, 2009.

  1. JNSamara

    JNSamara Member

    Hey guys

    I have a query regarding the derivation of the formula for u and d in the binomial tree model.

    Using equations (11.11) and (11.12) on pg 253....Hull goes on to show that

    exp(r*dt) (u+d) - ud = exp(2*r*dt) + sigma squared * dt

    however in the proof (Q&A Bank Part 2 Solutions Page 13 Step 1) they state that

    exp(r*dt) (u+d) - ud = exp(2*r*dt + sigma squared * dt)

    I have gone through the proof from the second equation and it seems fine. I also used the formula for u&d, plugged it into the first equation and got the answer in the first equation.

    Dont know whats going on...anyone? :)
     
  2. JNSamara

    JNSamara Member

    Nevermind

    I worked it out, sorry.

    exp(2*r*dt) + sigma squared * dt = exp(2*r*dt + sigma squared * dt)

    if you expand the exp and omit terms higher than dt.
     

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