NewStudent
Active Member
I recently completed studying through SP6 CMP for year 2021.
Please consider my list of doubts/questions and explain wherever necessary.
List of Doubts
1. SP6-09: Exotic Derivatives, Page 31 Q. 9.2 iii)
Old Values : r = In(1.05) = 4.879016417% , σ *√(1) = σ = In(1.25) = 22.31435513% , St = 480, Δ = 53.7
Now question states that r increases by 0.25%, σ increases by 1% and share price drops by 2.
In Acted Answer it considers % changes as it is without converting them into absolute changes.
If we assume that changes in r and σ are % changes then :
δr = +0.25% * 4.879016417% = +1.219754101 * 10^(-4)
δσ = 1% * 22.31435513% = +0.2231436%
δS = -2
δf = ΔδS + ρδr + Vδσ + ½*(δS)^2 * Γ (As per SP6-08 Page 14 Section 2.6 Box )
So my question why is Γ and its effect is ignored here? Surely we must incorporate it ?
If we ignore Γ term and continue, we get:
δf = 126.8634 and New f = Old f + δf = 11113.86 ≅ 11114
2. SP6-15 : Risk Management – Page 52, Q. 15.5 ii)
In 6th line from bottom, (Merton model to value shares), shouldn’t Theoretical share price at time 10 be denoted by S10 ? In answer it is denoted by S0.
3. SP6-15 : Risk Management – Page 57, Q. 15.9 ii)
On SP6-15 Page 45, Question states that £ 1 million is held in each bond. Portfolio has 2 corporate zero coupon bonds. So isn’t the total portfolio value is £ 2 million and
95 % VaR is (1-0.3) * £2m = £1.4m ? Why is Acted Answer (1-0.3) * £1m = £0.7m
4. SP6-16 : Credit Derivatives – Page 22, 23 Part ii)
Here, Probability and discount factors both are applied to Premiums, Claims and Accrual. But it is denoted by PV. Shouldn’t it be denoted by EPV (Expected Present Value) ?
Also, can you please explain (E)PV Accrual adjustment, and when and why it is required?
5. SP6-16 : Credit Derivatives – Page 44, Q. 16.5 ii)
Here, please mention that Assumption : Premium paid annually in advance.
Because in similar question (IFoA ST6 S2008 Q. 8 ii)) on SP6-16 Page 22, it is mentioned that
Assumption : Premiums P are paid annually in arrears.
6. SP6-17: Practical Derivative Management and Problem Solving – Page 31
In last line I did not understand the partial derivative.
Why it is -T* B(t, T*) instead of (t - T*) B(t, T*) ?
7. SP6 – X Assignments Questions : X5 – Page 2 Q. X 5.4)
The question numbering should be i), ii), iii) instead of only i) and ii)
8. SP6 – X Assignments Solutions : X2 – Page 7, Q. X 2.4) i)
In third line I did not understand why integral of Ys dWs from t1 to t2 is 0 given F t1 . Please explain
9. SP6 – X Assignments Solutions : X4 – Page 6, Q. X 4.5) ii)
The numerical accuracy of final answer (18.9%) is low. Accurate answer is 17.850369%.
I am pasting values from Excel for reference
St Log Return
298 0.010016778 =LN(A3/A2) Answer 17.85036904%
301 -0.006666691 =LN(A4/A3) =STDEV.P(B2:B10)*SQRT(250)
299 0.006666691 =LN(A5/A4)
301 0.029462033 =LN(A6/A5)
310 0.016000341 =LN(A7/A6)
315 -0.009569451 =LN(A8/A7)
312 0 =LN(A9/A8)
312 0 =LN(A10/A9)
312 0.003200003 =LN(A11/A10)
313
Note : In 1-Var Stat mode in calculator, I had entered data values as In(S / S[i-1] ) and used statistical function σ directly to calculate daily standard deviation.
The list is long as I have aggregated all my doubts in a single post.
Thanks in advance for your help.
Please consider my list of doubts/questions and explain wherever necessary.
List of Doubts
1. SP6-09: Exotic Derivatives, Page 31 Q. 9.2 iii)
Old Values : r = In(1.05) = 4.879016417% , σ *√(1) = σ = In(1.25) = 22.31435513% , St = 480, Δ = 53.7
Now question states that r increases by 0.25%, σ increases by 1% and share price drops by 2.
In Acted Answer it considers % changes as it is without converting them into absolute changes.
If we assume that changes in r and σ are % changes then :
δr = +0.25% * 4.879016417% = +1.219754101 * 10^(-4)
δσ = 1% * 22.31435513% = +0.2231436%
δS = -2
δf = ΔδS + ρδr + Vδσ + ½*(δS)^2 * Γ (As per SP6-08 Page 14 Section 2.6 Box )
So my question why is Γ and its effect is ignored here? Surely we must incorporate it ?
If we ignore Γ term and continue, we get:
δf = 126.8634 and New f = Old f + δf = 11113.86 ≅ 11114
2. SP6-15 : Risk Management – Page 52, Q. 15.5 ii)
In 6th line from bottom, (Merton model to value shares), shouldn’t Theoretical share price at time 10 be denoted by S10 ? In answer it is denoted by S0.
3. SP6-15 : Risk Management – Page 57, Q. 15.9 ii)
On SP6-15 Page 45, Question states that £ 1 million is held in each bond. Portfolio has 2 corporate zero coupon bonds. So isn’t the total portfolio value is £ 2 million and
95 % VaR is (1-0.3) * £2m = £1.4m ? Why is Acted Answer (1-0.3) * £1m = £0.7m
4. SP6-16 : Credit Derivatives – Page 22, 23 Part ii)
Here, Probability and discount factors both are applied to Premiums, Claims and Accrual. But it is denoted by PV. Shouldn’t it be denoted by EPV (Expected Present Value) ?
Also, can you please explain (E)PV Accrual adjustment, and when and why it is required?
5. SP6-16 : Credit Derivatives – Page 44, Q. 16.5 ii)
Here, please mention that Assumption : Premium paid annually in advance.
Because in similar question (IFoA ST6 S2008 Q. 8 ii)) on SP6-16 Page 22, it is mentioned that
Assumption : Premiums P are paid annually in arrears.
6. SP6-17: Practical Derivative Management and Problem Solving – Page 31
In last line I did not understand the partial derivative.
Why it is -T* B(t, T*) instead of (t - T*) B(t, T*) ?
7. SP6 – X Assignments Questions : X5 – Page 2 Q. X 5.4)
The question numbering should be i), ii), iii) instead of only i) and ii)
8. SP6 – X Assignments Solutions : X2 – Page 7, Q. X 2.4) i)
In third line I did not understand why integral of Ys dWs from t1 to t2 is 0 given F t1 . Please explain
9. SP6 – X Assignments Solutions : X4 – Page 6, Q. X 4.5) ii)
The numerical accuracy of final answer (18.9%) is low. Accurate answer is 17.850369%.
I am pasting values from Excel for reference
St Log Return
298 0.010016778 =LN(A3/A2) Answer 17.85036904%
301 -0.006666691 =LN(A4/A3) =STDEV.P(B2:B10)*SQRT(250)
299 0.006666691 =LN(A5/A4)
301 0.029462033 =LN(A6/A5)
310 0.016000341 =LN(A7/A6)
315 -0.009569451 =LN(A8/A7)
312 0 =LN(A9/A8)
312 0 =LN(A10/A9)
312 0.003200003 =LN(A11/A10)
313
Note : In 1-Var Stat mode in calculator, I had entered data values as In(S / S[i-1] ) and used statistical function σ directly to calculate daily standard deviation.
The list is long as I have aggregated all my doubts in a single post.
Thanks in advance for your help.