PBOR CS1 Truncated notes in the text files

Discussion in 'CS1' started by Andrew Brown, Mar 16, 2022.

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  1. Andrew Brown

    Andrew Brown Member

    I am reviewing the CS1 PBOR exercise.
    the gibberish � marks are unacceptable. you should do better, you would rather give us the results in pdf or word format and not the text format which corrupts the special characters

    It is frustrating.

    see below
    #Exercise 5.01
    #-------------------------------------------------------------
    #(i) Empirical unconditional distribution
    #Calculation of theoretical mean and variance
    #E[X] = E[E(X|P)] = E[nP] = nE[P] = 12*0.4 = 4.8

    #var[X] = E[var(X|P)] +var[E(X|P)] = E[nP(1-P)] + var[nP]
    # = n(E[P]-E[P�])+ n�var(P) = n(E[P]-(var[P]+E�[P]))+ n�var(P)
    # = 12(0.4 - (0.04+0.4�)) + 12�*0.04
    # = 8.16

    #---------------------------------------
     
  2. John Lee

    John Lee ActEd Tutor Staff Member

    They're given in "text format" as they are .R files which can be run in R, rather than PDFs or word documents which can't.

    Whilst they're fine in my R file, it appears that the new system we are using to host the PBOR has corrupted them. I've changed the file and will have it uploaded to the PBOR. I'd attach here but the discussion forum software doesn't allow .R uploads.

    If you are aware of plugins that allow .R files to work smoothly with discussion forums and website hosting then I'd be grateful if you could let us know.
     
    SHAHKAR HUSSAIN and Andrew Brown like this.
  3. Andrew Brown

    Andrew Brown Member

    Thanks a tone Lee. The var[p] i assume i approximated to 2 decimal places, 0.04 , i suppose you used beta distribution for Var, , closer answer for var p=0.038.
     
  4. John Lee

    John Lee ActEd Tutor Staff Member

    Are you referring to the theoretical distribution of the prior p~beta(2,3)?
    In which case the mean is 2/(2+3) = 0.4 and the variance is exactly (2*3)/(2+3)^2(2+3+1) = 0.04.
     
    Andrew Brown likes this.

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