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October 2014 QP: Question 5

vidhya36

vidhya36

Very Active Member
How did they calculate the integral while computing Sx?
1. If they are using Uy, why haven't they changed the value to 1/w-y, i.e., in terms of y?
2. Integral of 1/x is log x and not log (1/x). So, how did they arrive at the step in the third line?
 
vidhya36 said:
How did they calculate the integral while computing Sx?
1. If they are using Uy, why haven't they changed the value to 1/w-y, i.e., in terms of y?
2. Integral of 1/x is log x and not log (1/x). So, how did they arrive at the step in the third line?
Click to expand...

1. they should.

2. but (integral of -1/x)= - ln(x)= ln(1/x)
 
I cant understand in this question, how the E(Tx) and E(Tx^2) is calculated? Kindly help understand me.
 
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