1. Posts in the subject areas are now being moderated. Please do not post any details about your exam for at least 3 working days. You may not see your post appear for a day or two. See the 'Forum help' thread entitled 'Using forums during exam period' for further information. Wishing you the best of luck with your exams.
    Dismiss Notice

Negative Binomial Distribution

Discussion in 'CT3' started by kartik_newpro, Jul 3, 2011.

  1. kartik_newpro

    kartik_newpro Member

    Can someone outline the differences between Type I and Type II Negative Binomial Distribution and how to identify which is it?

    I would be grateful if it is done both in the theoretical and practical sense (with example).

  2. John Lee

    John Lee ActEd Tutor Staff Member

    Type 1 counts the number of trials up to and including the kth success.

    Type 2 counts the failures before the kth success.

    So suppose we are counting the number of goals we score (success) for the penalty kicks we make (trials).

    Suppose we score our 3rd goal on our 10th penalty kick.

    Under Type 1 X=10 as it is the 10th kick when we got our 3rd goal.

    Under Type 2 X=7 as we had 7 failures before we got our 3rd goal.

    In CT3 our default choice will be a type 1 (for CT6 it will be type 2).
  3. stylz

    stylz Member

    Following on from this, in the exam type question on page 13, chapter 7, it specifies a negative binomial distribution for N. In the answer it says that it is a type 2 negative binomial distribution.

    I'll have a go at writing the pdf here, but it's hard to get the format right in these text boxes.

    The first part is an nCr format, where n = n+2, and r = n. This is then multiplied by 0.9^3x0.1^n.

    Might be easier if you just look at the notes yourself to see the pdf clearly (or someone can tell me how to write the formula properly in this text box).

    My question is, how is this easily identified as a type 2? My initial thought was type 1. Cheers
  4. didster

    didster Member

    couple of pointers

    if n=0,1,2,.. then it's number of failures so type 2; n=k,k+1,... =>type 1.

    in your formula
    the probabilities have n failures : (P(failure))^n
    n+2 things being arranged: again hints at n failures, final success is fixed at end and n+2 other results to arrange.
  5. stylz

    stylz Member

    Ok that help didster. Thanks. But what you are saying is in contrast to the book which says type 2....??
  6. didster

    didster Member

    No, in your example, n represents the number of failures, so type 2
    Look at it again.

Share This Page