• We are pleased to announce that the winner of our Feedback Prize Draw for the Winter 2024-25 session and winning £150 of gift vouchers is Zhao Liang Tay. Congratulations to Zhao Liang. If you fancy winning £150 worth of gift vouchers (from a major UK store) for the Summer 2025 exam sitting for just a few minutes of your time throughout the session, please see our website at https://www.acted.co.uk/further-info.html?pat=feedback#feedback-prize for more information on how you can make sure your name is included in the draw at the end of the session.
  • Please be advised that the SP1, SP5 and SP7 X1 deadline is the 14th July and not the 17th June as first stated. Please accept out apologies for any confusion caused.

Markov Chain Question

N

Nappy

Member
Hi Guys,

Can anyone answer part (iii) from the attached picture. I can't work it out.

Thanks

N

upload_2017-1-30_13-42-27.png
 
Hi Guys,

Can anyone answer part (iii) from the attached picture. I can't work it out.

Thanks

N

View attachment 550

The transition matrix is
P = \begin{matrix} 1/3 & 2/3 & 0 \\ 1/3 & 0 & 2/3 \\ 0 & 1/3 & 2/3 \end{matrix}

Let m_i be the expected number of policy years until the new policyholder reaches level 2 given currently he is in level i.
So we can form the following equations:
$$m_0 = 1 + 1/3 m_0 + 2/3 m_1$$

$$m_1 = 1 + 1/3 m_0 + 2/3 m_2$$

Note that we are adding 1 as the policyholder changes levels only after 1 year. Also m_2 = 0.
Solving the equations we get m_0 = 3.75 years. This should be the answer. Let me know if I have erred somewhere.
 
Last edited by a moderator:
Probability of no accident is 1/3. So, I guess the values 1/3 and 2/3 in the matrix should be swapped.
 
Back
Top