Joint distribution Practice Question (Convolution)

Discussion in 'CS1' started by Thabo Motaung, Dec 26, 2022.

  1. Thabo Motaung

    Thabo Motaung Member

    Good day

    There is a question where we are given X ~ chi_square(m), Y ~ chi_square(n) and we need to use convolution to show that X + Y ~ chi_square(m+n). On the memo they use the substitution t = x/z and the upper bound of the integral changes from z to 1. How did they get to change that z to a 1 because I do not understand that part? I guess it makes sense because the integral just evaluates to a Beta pdf but I just do not understand how the z changes to a 1.

    Best
     
  2. Andrea Goude

    Andrea Goude ActEd Tutor Staff Member

    Hi Thabo
    I am assuming this is from practice question 4.10, the limits of x go from 0 to z, so the limits of t go from 0 to 1, as t=x/z the upper limit of t is z/z, which is where the 1 is from.
     

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