Hi everyone, I'm looking for an explanation of a step in Example 10.6, Chapter 10 (Point Estimation) of the CT3 material. The integral is: /inf | 2cx exp(-cx^2) dx = [-exp(cx^2)] from 6 to inf. = exp((c)(6^2)) /6 It looks like they have just taken the derivate of (-cx^2) i.e. (-2cx), taken its inverse (-1/2cx), then it cancels out the (2cx) already there leaving you with (-1)...is this right? Thanks!
Yes - you can either do this by "inspection", ie noting that: d/dx exp{f(x)} = f'(x) exp{f(x)} and so reversing this or by using integration by substitution.
