Independent Increments-Ch4

Discussion in 'CS2' started by Actuary@22, Jan 23, 2021.

  1. Actuary@22

    Actuary@22 Very Active Member

    Hi
    I didn't get the first line on Pg 9 of Ch-4.If the processes are independent so how can we generalise and conclude that the increments are independent as well?
    Kindly explain.
    Thank you
     
  2. Andrew Martin

    Andrew Martin ActEd Tutor Staff Member

    Hello

    If process A is independent of process B then changes in process A are independent of changes in process B. ie if the values of process A have no impact on / relationship with process B and vice versa, then the changes in value of process A have no impact on / relationship with the changes of value for process B.

    Say we have discrete valued processes then:

    \( P(A_{s_1} - A_{t_1} = a, B_{s_2} - B_{t_2} = b) = \Sigma_{v_1} \Sigma_{v_2} P(A_{t_1} = v_1, A_{s_1} = v_1 + a, B_{t_2} = v_2, B_{s_2} = v_2 + b) \)

    \( = \Sigma_{v_1} \Sigma_{v_2} P(A_{t_1} = v_1, A_{s_1} = v_1 + a) * P(B_{t_2} = v_2, B_{s_2} = v_2 + b) \)

    by independence of \( \{A_t\} \) and \( \{B_t\} \).

    \( = \Sigma_{v_1} P(A_{t_1} = v_1, A_{s_1} = v_1 + a) * \Sigma_{v_2} P(B_{t_2} = v_2, B_{s_2} = v_2 + b) \)

    \( = P(A_{s_1} - A_{t_1} = a) * P(B_{s_2} - B_{t_2} = b) \)

    therefore they are independent.

    Hope this helps

    Andy
     

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