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IAI October 2009 Examination Q6

P

paryas.bhatia

Member
Please check the solution of this question and please tell what has been done in the 6th step (counting from the very start). How does sigma from 2 to infinity changes to sigma from 1 to infinity and why is lemda multiplied and how does the x-1! term becomes x!?
 
Hi I think you want to know how poison for for lambda forem has been converted into labmda (1-e-lambda)??

If yes, then we have used just the expansion of e-lambda. the poisson function is
lambda ^x e-lambda/xfact
Expand the series from 1 and convert into e-lambda
Using e^lambda=1+labmda+labda^/2fact

Try to solve yourself and you would get it
Let me know if there is any other step you were referring to
 
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