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IAI Oct 2009 Q12 (ii)

C

Chandrima

Member
I wanted to check out the solution of Q12(b) , but could not follow how L(theta) was derived by them. Can anyone elaborate? I'm posting the pic of solution but their solution sheet itself is very unclear and not clearly visible.
 

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The likelihood function is just the PDF of Poisson distribution where they've replaced lambda with xtheta.
Given the mean of distribution is equal to xtheta
 
Aditya mohan mathur said:
The likelihood function is just the PDF of Poisson distribution where they've replaced lambda with xtheta.
Given the mean of distribution is equal to xtheta
Click to expand...
Thank you so much sir. I made a mistake in one step (in attached pic where I wrote 'imp. step'). I took it as lambda^ny instead of lambda^summation of Yi. Now I rectified it.
 

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