(a) Since p = 1/365 and q = 364/365 The probability of occurring one person's birthday is [1/365] The probability of occurring two person's birthday is [1/365] * [1/365] In a complete year the probability of occurring two person's birthday is [ [1/365] * [1/365] * 365 ] = 0.002740 (b) Say X is the number of birthdays, and hence X ~ Bin (3 , 1/365) In a complete year occurring of at least two person birthdays is P[ X => 2] * 365 = [ P [ X = 2 ] + P [ X = 3] ] * 365 = [3C2 * (1/365)^2 * (364/365)^(3 - 2) + 3C3 * (1/365)^3 * (364/365)^0 ] = 0.008204 Similarly Say X is the number of birthdays, and hence X ~ Bin (4 , 1/365) In a complete year occurring of at least two person birthdays is P[ X => 2] * 365 = [ P [ X = 2 ] + P [ X = 3] + P [ X = 4] ] * 365 = [4C2 * (1/365)^2 * (364/365)^(4 - 2) + 4C3 * (1/365)^3 * (364/365)^1 + 4C4 * (1/365)^4 * (364/365)^0 ] * 365 = 0.016356 (c) Say X is the number of birthdays, and hence X ~ Bin (15 , 1/365) In a complete year occurring of at least two person birthdays is P[ X => 2] * 365 = [ 1 - P[ X < 2] ] * 365 = 0.25
In the question it was asked us to get the probability as a whole i.e., for 365 days. That's why we have multiplied it with 365 days.