IAI may 2006 Q 31

Discussion in 'CT7' started by shdh, Sep 9, 2016.

  1. shdh

    shdh Ton up Member

    In the above question, why did MR of poor be p(1-1/3)?

    How was the solution arrived at?

    Thanks!
    Regards,
    Shyam
     
  2. Whippet1

    Whippet1 Member

    Q= 1/(P^3)

    So: Q * P^3 = 1, which means P^3 = Q^(-1), ie P = Q^(-(1/3))

    Now: TR = P*Q = Q^(-(!/3))*Q = Q^(2/3)

    So: MR = dTR/dQ = 2/3 * Q^(-(1/3)) = 2/3 * P = P*(1 - 1/3)

    Hope this helps. :)
     

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