but am having problems working out values of A and B in following equation.... A(X + 4) + B(2X + 1) = 2X^2 + 14X + 10 Can't seem to work it out....just wondered if anyone else knows... any help appreciated.... Madge
1. Multiply LHS out so you can get terms in x^2, x and constant 2. You should get 0 terms in x^2, (A+2B) terms in x and (4A+B) terms in the constant so: A+2B=14 and 4A+B= 10 3. You can now solve these 2 eqns simultaneously. ps if you feel that your algebra isn't up to scratch you I think the Foundation ActEd Course (FAC) should help.
Hi Madge An answer is A = 2, B = (2x + 2) Giving: 2(2x + 1) + (2x + 2)(x+4) = 4x + 2 + 2x^2 + 8x + 2x + 8 = 2x^2 + 14x + 10