I expect this is a really obvious question

[madge]

but am having problems working out values of A and B in following equation....

A(X + 4) + B(2X + 1) = 2X^2 + 14X + 10

Can't seem to work it out....just wondered if anyone else knows...

any help appreciated....

Madge

 

[veeko]

1. Multiply LHS out so you can get terms in x^2, x and constant
2. You should get 0 terms in x^2, (A+2B) terms in x and (4A+B) terms in the constant so:
A+2B=14 and
4A+B= 10
3. You can now solve these 2 eqns simultaneously.

ps if you feel that your algebra isn't up to scratch you I think the Foundation ActEd Course (FAC) should help.

 

[veeko]

Sorry madge I think my solution was incorrect! My terms in x^2 dont match up.

 

[Gareth]

it is insoluable, you need some x^2 terms on the LHS.

 

[Abi]

Hi Madge

An answer is A = 2, B = (2x + 2)
Giving:
2(2x + 1) + (2x + 2)(x+4) = 4x + 2 + 2x^2 + 8x + 2x + 8
= 2x^2 + 14x + 10

 

[madge]

thanks v much veeko, gareth abi...

help really appreciated...