• We are pleased to announce that the winner of our Feedback Prize Draw for the Winter 2024-25 session and winning £150 of gift vouchers is Zhao Liang Tay. Congratulations to Zhao Liang. If you fancy winning £150 worth of gift vouchers (from a major UK store) for the Summer 2025 exam sitting for just a few minutes of your time throughout the session, please see our website at https://www.acted.co.uk/further-info.html?pat=feedback#feedback-prize for more information on how you can make sure your name is included in the draw at the end of the session.
  • Please be advised that the SP1, SP5 and SP7 X1 deadline is the 14th July and not the 17th June as first stated. Please accept out apologies for any confusion caused.

Have a ques... April 04, 103 Ques 3

MindFull

Ton up Member
Last edited:
no repliess....

:confused: Hi!

Is there a reason why noone is answering my question from the past paper?
Any reply would be appreciated. Thanks.
 
Hi
The rate at which N(t) is increasing by 1 is given as lambda, regardless of what the value of N(t) is. But the rate at which N(t) is decreasing is expressed as the rate mu per life. So if N(t)=1, the rate at which one death would be occurring would be mu. But if N(t)=n, the rate at which 1 death would be occurring would be n-times faster than this, ie n(mu).

pn is the probability of staying in the same state n. The forward d.e for pn is:

- Sum(all rates of leaving the end state n) x pn + Sum(all rates of entering the end state n from all other states) x p(other state)

This is the same form as the general eqn shown on page 33 of the Tables. The first part of the equation in this question is second part of the equation in the tables! - that's all.

Can you see it now? Shout again if you can't.
(I'm not around again till thursday though - but someone else could have a go?)
Enjoy.
 
Back
Top