Graduation - Individual Standardised Deviations Test

Discussion in 'CT4' started by CorkActuary, May 19, 2014.

  1. CorkActuary

    CorkActuary Member

    You know where you are comparing the Expected with the observed interval readings to see whether or not there is a skewness in standard deviations.. Where are the expected values derived from? Are there something to do with distribution of standard curve?

    E.g.
    Interval: (-3,-2) (-2,-1) (0,-1) (0,1) (1,2) (2,3)
    Expected: 0.2 1.4 3.4 3.4 1.4 0.2
    Observed: 0 0 6 2 2 0

    There is an obvious symmetry to the expected values but from where are they derived?
     
  2. r_v.s

    r_v.s Member

    In a normal distribution, you expect roughly 68% values to lie between (mu - sigma) and (mu +sigma).
    In the standard normal case, mu =0, sigma =1.
    Therefore you should have 68% values in (-1,1).
    Due to symmetry, 34% should lie within (-1,0) and another 34% in (0,1).

    In your case you would have in all 10 values. So 3.4 each in (-1,0) and (0,1).
    Then look at (mu-2 sigma) to (mu +2 sigma).
    Here you should have 96% of all the values.
    Hence the next 14% from (-2,-1) and (1,2)
    and so on...
     
  3. CorkActuary

    CorkActuary Member

    Thanks... Hopefully, different parameter values for mu and sigma won't be asked... :(
     
  4. r_v.s

    r_v.s Member

    Cheer up!! they wont!! You are expected to compare the values with a standard normal curve!! :)
     
  5. CorkActuary

    CorkActuary Member

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