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Glm A2007 Q10

P

ping2002

Member
the b(theta) = log u.

How could the answer gives

b'(theta) = u ???????
 
so we know that

theta = -1/mu

Therefore
mu = -1/theta

b(theta) = log u
= -log(-theta)

b'(theta) = (-1/-theta)*-1
= -1/theta
= mu

*Remember when you differentiate a log you must also differentiate the theta in brackets, in this case = -1

Hope this helps

Ed
 
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