forward price value

Discussion in 'CT1' started by mayughodake9, Apr 13, 2014.

  1. mayughodake9

    mayughodake9 Member

    Q from april 2007
    An investor entered into a long forward contract for a security 5 years ago and the contract is due to mature in 7 years’ time. The price of the security was £95 five years ago and is now £145. The risk-free rate of interest can be assumed to be 3% per annum throughout the 12 year period.
    Assuming no arbitrage, calculate the value of the contract now if
    (i) The security will pay dividends of £5 in two years’ time and £6 in four years’ time.
    (ii) The security has paid and will continue to pay annually in arrear a dividend of 2% per annum of the market price of the security at the time of payment.


    0 (95) ............ 5(145)................... 12

    tell m sir

    1) is value of forward contract give the future value? i.e it give value of 5 to 12 year period.

    2) pls find attachment and explain me detail what actualy done in solution?.
     

    Attached Files:

    Last edited by a moderator: Apr 13, 2014
  2. Hemant Rupani

    Hemant Rupani Senior Member

    value of a forward contract is not a future value, it's a current surplus/deficit value, i.e. value of the forward contract for this situation is surplus/deficit at point 5. that is what is solved in solution.
     
  3. mayughodake9

    mayughodake9 Member

    value

    means it give the value at 5. m i correct?

    can u give me email id hemant?
     
  4. Hemant Rupani

    Hemant Rupani Senior Member

    means, It'll give the surplus/deficit value at point of time.

    r.act.hemant@gmail.com
     
    Last edited: Apr 16, 2014
  5. Srijan Ghosh

    Srijan Ghosh Member

    sir can u plz help me with the sol of above stated question

    according to me the ans should be
    1) k(0) = (S(0)-I)*(1+i)^T = 95*1.03^12-5*1.03^2-6*1.03^4=123.389
    k(5) = S(5)*(1+i)^(T-r) = 145*(1+i)^7=178.33

    hence V(l)=(K(5)-K(0))*(1+i)^-7 = 44.67 ≠ 39.39


    2) k(0) = s(0)*e^( δ-0.02)12=106.5468
    k(5) = S(5)*e^( δ-0.02)7=155.034

    hence V(l)=(K(5)-K(0))*e^(-(δ-0.02)7)=45.34

    the answer in the attachment is is preety much different and difficult plz help....
     
  6. John Lee

    John Lee ActEd Tutor Staff Member

    Since the payments are 5 at time 7 and 6 at time 9, you should have:

    \(K_0 = 95*1.03^12 - 5*1.03^5 - 6*1.03^3 = 123.09\)

    Your \(K_5\) has ignored the two payments altogether! You should have:

    \(K_5 = 145*1.03^7 - 5*1.03^5 - 6*1.03^3 = 165.98\)

    Hence the value at time 5 is:

    \(V_5 = (K_5 - K_0)v^7 = 34.87\)
     
  7. bobbathejobba

    bobbathejobba Member

    You ask a lot of questions but haven't said thank you once :(
     

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