If a) I understand what you are asking and b) my memory of that material is sufficiently good (I got an exemption from Uni),
I would have thought that it would have involved a product of the 2 items you have there along with a 10 C 4 factor.
ie P(X<=m)^(n-x)*P(X>m)^x* (n C x), observed value of x is 6, n=10.
Of course if you (or the question) mean by "calculate the likelihood", calculate a function of the likelihood in order to maximise it (rather than the absolute number = likelihood), then you could always knock off constants like the n C x.
(I originally had 10 C 4 but thought that it should be n C x, which then made it non-constant. However I think in maximising likelihoods the x is known and then we can treat it all as constants, The variable being the parameters of the distribution)
Who knows (and I'm really guessing here), if you play with it long enough you could even find a constant to knock off that allows you to just include the P(X>m)^x
Hope that helps some. Does that make any sense at all? The more I think about it myself the worse it seems to me.
Last edited by a moderator: Jul 18, 2007