for this type of situation,
there are two ways
i) work yearly
\[35000\times13\times v^{13}+15000\times(10\times v^{10}+10.5\times v^{10.5} ............) \] so on
ii) work semi-annualy,
\[35000\times 26\times v^{26}+15000\times(20\times v^{20}+21\times v^{21} .............) \]
and then apply Ia
then divide solution by 2 to get annual term.
Last edited: May 15, 2014