Differentiating a summation

Discussion in 'CT6' started by hatton02, Mar 26, 2013.

  1. hatton02

    hatton02 Member

    On the GLM chapter and on one of the answers it goes from:

    ln L (mu_ij) = sum over i sum over j (- mu_ij + y_ij ln mu_ij) + const

    Then:

    d ln L/d mu_ij = -1 + y_ij/mu_ij = 0.

    Why have the summations been ignored? I was trying to put some values of i and j in there to get rid of the summations but I got confused with what it means.

    Indeed in the next question it's a very similar thing but with no ij subscripts on the mu but they keep the summations. Anyone help please?

    (Apr 2004 question 9)
     
  2. John Lee

    John Lee ActEd Tutor Staff Member

    Suppose we consider mu13 - only one of all the 12 summations has this particular term - so when we differentiate with respect to mu13 we'll only get that particular part of the summation.

    Whereas mu is in all of the 12 summations - so they stay when we differentiate.

    Does that help?
     

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