okay well ggrzz was sort of on the right track but is still incorrect so I will explain it again
For iii)
Theres sort of 2 parts here
*Lets say you are the first passenger to arrive: this means you still need to wait for 3 more passengers to arrive, this is expected to take 3*Beta
*If you are the 2nd passenger to arrive: this means you still need to wait for 2 more passengers to arrive, this is expected to take 2*Beta
*If you are the 3rd passenger to arrive: this means you still need to wait for 1 more passenger to arrive, this is expected to take Beta
*If you are the 4th passenger to arrive, this means you leave immediately and the expected time is 0
Now we need to consider the probability of arriving 1st 2nd 3rd or 4th -> here we assume that each is equal by the way the question is worded
so each case occurs with probability 1/4
therefore the EXPECTED waiting time is 1/4(3*beta + 2*beta +beta) = 3/2*Beta
Last edited by a moderator: Apr 7, 2011