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CT3 CH7 Conditional Expectation Q7.5&7.7

S

Sunil Sanga

Member
In question 7.5
Variable K has an exp(lemda).

For a given value of K, random variable X has an Poisson (k)

Part 1) expression of E(X/K)

Can anyone explain why the solution is not given as per standard formula of Conditional Expectation form instead of below -
E(X/K=k)=k
And same goes for Variance in Q 7.7
 
Because you don't need to calculate E(X|K=k) from scratch as you are given the distribution of X|K and so you can sipl look up the mean and variance in the Tables.
 
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