S
Sunil Sanga
Member
In question 7.5
Variable K has an exp(lemda).
For a given value of K, random variable X has an Poisson (k)
Part 1) expression of E(X/K)
Can anyone explain why the solution is not given as per standard formula of Conditional Expectation form instead of below -
E(X/K=k)=k
And same goes for Variance in Q 7.7
Variable K has an exp(lemda).
For a given value of K, random variable X has an Poisson (k)
Part 1) expression of E(X/K)
Can anyone explain why the solution is not given as per standard formula of Conditional Expectation form instead of below -
E(X/K=k)=k
And same goes for Variance in Q 7.7