In question 7.5 Variable K has an exp(lemda). For a given value of K, random variable X has an Poisson (k) Part 1) expression of E(X/K) Can anyone explain why the solution is not given as per standard formula of Conditional Expectation form instead of below - E(X/K=k)=k And same goes for Variance in Q 7.7
Because you don't need to calculate E(X|K=k) from scratch as you are given the distribution of X|K and so you can sipl look up the mean and variance in the Tables.
