Hii all, sec.-4 page 14- In the example given on the top, while calculating values of h1 and h2 as we have various possible values for h1 and h2 satisfying the given condition of probability...e.g. for h1, x<0 and x<1 ..similarly for h2, values from x>11 to x>19 satisfying the condition. so why h1=1 and h2= 11 is taken??? why other values are ignored?? anyone plz rply asap..i shal be thankful
Use the binomial probability tables on page 188 of your tables. You are trying to find x such that P(X<=x) = 2.5% and the y such that P(X >=y) 2.5% If it's between 2 values go for the one with the smaller probability. But this is not needed to answer the exam questions.
