Hi, I hope I'm not missing something simple here - - > in the solutions on pg13 of the notes (Chp 7), what happens to the (beta(i)^2 * VM) in the bracket for the specific risk? In the next workings line, only the (V error term, i) remains. Does the variable above go to zero? Thanks
Hi Look at the indicies of the double summation terms. The \(\beta_i^2 V_M\) term is captured by the double summation when the \(j \neq i\) condition is removed. Hope that helps.