Chapter-3 page-40

Discussion in 'CT4' started by nluashok, Feb 20, 2014.

  1. nluashok

    nluashok Member

    Hi,

    2 Lines from Chapter-3 under heading "7.2 Assessing the fit":

    If the Markov property holds we expect nijk to be an observation from
    a Binomial distribution with parameters nij and pjk .

    It would be very helpful if you explain same.

    Regards,
    Ashok
     
  2. suraj

    suraj Member

    I am explaining the line of top of Page 40
    and using example Q 3.17 as an aid.

    Let's say we want to find the distribution of \(N_{12}\) given \(N_1\).
    i.e. no. of transitions from state 1 to 2 given Number of times the process was in state 1.

    Now if the process is in state 1, after a transition takes place it can either remain in state 1, or go to state 2 or 3.

    Transition to state 2 can be taken as a success, and transition to state 1 and 3 a failure.

    So distribution of \(N_{12}\) given \(N_1\) is \(Bin(N_1, ~ p_{12})\).
    Now we want to estimate \(p_{12}\) from the data given.

    11
    12
    12
    13
    13
    13

    These are the observations from the data set. So, 6 times the process was in state 1 and after a transition took place, 2 times it went to state 2.

    So \(\widehat{p}_{12}= \frac{2}{6}\)
    Similarly \(\widehat{p}_{11} = \frac{1}{6} and ~\widehat{p}_{13}= \frac{3}{6}\)

    Therefore distribution of \(N_{12}|N_1\) is \(Bin(N_1,~ \frac{2}{6})\).

    or in general distribution of \(N_{ij}|N_i\) is \(Bin(N_i,~ p_{ij})\).

    You can apply the same logic to triplets as well, which was your doubt.
     
    Last edited by a moderator: Feb 22, 2014
  3. Lewin

    Lewin Member

    confused

    I have a querry on Q. 3.17

    The question states:

    You have been given the following series of data from a 3 state process:

    1,3,2,2,1,3,3,2,3,1,2,3,2,1,1,2,2,1,3,3.

    i)calculate the values of n(i), n(i,j) and n(i,j,k)

    ii) Estimate the one step transition probabilities.



    a) The answers give n(3)=6, however, i count 7 entries.

    b)The transition probability P(33) is given as 2/6,which is n(33)/n(3),implying n(3,3)=2 however, the answers state n(33) as 1, since final entry 3,3 is ignored.

    So, is n(3,3) 2 or 1?

    Why is n(3)=6?

    Anyone kindly assist.
     
    Last edited by a moderator: May 22, 2014
  4. Julie Lewis

    Julie Lewis Member

    When estimating p(3,3), we count the number of times 3 is followed by 3 and then divide this by the number of times that 3 is followed by anything.

    The number of times that 3 is followed by anything is 6. We don't count the 3 at the end of the list as it's not followed by anything.
     
  5. Lewin

    Lewin Member

    Get it now.

    Thanks
     

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