chapter 2

Discussion in 'CT5' started by Neetu Verma, Feb 4, 2009.

  1. Neetu Verma

    Neetu Verma Member

    Hi,
    Can anyone explain me,In the derivation of EPV of immediate annuity payable continuously .Why we take w= -tPx ????? ( in chapter 2 ,topic-continuous annuities)
     
  2. rsmallela

    rsmallela Member

    Integration by substitution

    Well, this can be explained as follows:

    dw
    --- = tpx * (mu)x+t.
    dt

    (read tpx as survival probability ..can't post its notation here..!)

    We need to integrate it wrt to t to get w.
    It becomes: w = Integral of (tpx * (mu)x+t * dt) ... (1)

    Insert full form of tpx: exp(-integral 0 to t: (mu)x+s ds).

    Then (1) becomes:

    w = Integral of [ (exp(-integral 0 to t: (mu)x+s * ds)) * (mu)x+t * dt] ... (2)

    Using integration by substitution:
    Let K= [integral 0 to t: (mu)x+s * ds] ...these are components of tpx.
    Then dk/dt = [(mu)x+t] => dk = (mu)x+t * dt

    [Note, after substituting the upper and lower integral limits of t and 0, the (mu)x term becomes zero because it does not have a 't' in it and hence a constant when we differentiate wrt t. ]

    Substitute this in (2) above:

    w = Integral of [ (exp(-K) ) * dk ]
    => - exp (-K)

    Substitute back K:

    w = - exp (-[integral 0 to t: (mu)x+s * ds])
    = - tpx.

    therefore w = -tpx.


    Another idea is: Try from the other end..i.e. try to differentiate 'w' wrt to t i.e. find out dw/dt, after expanding tpx into exponential function. You will end up with tpx * (mu)x+t.

    if not clear, pls let me know...

    Thanks,
    Raj
     
  3. Neetu Verma

    Neetu Verma Member

    Thanks for clarifying Raj.
     

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