P
Purple
Member
In Section 2.4 of Chapter 18, the Pure Premium formula, (PP) is given as (X1+X2+X3+.....+XN)/n, where n=exposures, while aggregate losses, L=X1+X2+......+XN.
Why are the formulae for the variance and Expected value of PP|N as follows?
Var(PP|N) = Nσ(s )^2
E(PP|N)=Nμ(s )
Shouldn't the above be the variance and expected value of L|N?
Shouldn't the variance and expected value of PP|N be as follows:
Var(PP|N) = (Nσ(s )^2)/(n^2)
E(PP|N)=(Nμ(s ))/n
Please advise. Thank you.
Why are the formulae for the variance and Expected value of PP|N as follows?
Var(PP|N) = Nσ(s )^2
E(PP|N)=Nμ(s )
Shouldn't the above be the variance and expected value of L|N?
Shouldn't the variance and expected value of PP|N be as follows:
Var(PP|N) = (Nσ(s )^2)/(n^2)
E(PP|N)=(Nμ(s ))/n
Please advise. Thank you.