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Chapter 1

Discussion in 'CS2' started by Kanishka, Feb 11, 2020.

  1. Kanishka

    Kanishka Active Member

    Can someone please explain the example given under the increments section?
     
  2. Andrew Martin

    Andrew Martin ActEd Tutor Staff Member

    Hello

    The key assumption here is that the return on the stock depends on the duration of time considered but not on the start time. These are denoted by u and t respectively in the example. We also denote the price of the stock at time t as \( S_t \) and the return from time t to time (t+u) as \( S_{t + u} / S_t \).

    So, we are assuming that \( S_{t + u} / S_t \) does not depend on t. However, as written this doesn't look like an increment, which is what this section is all about. We can do a little manipulation to make an increment that looks similar by instead considering the log of the process:

    let \( X_t = log(S_t) \) then we have \( X_{t+u} - X_{t} = log(S_{t+u}) - log(S_{t}) = log(S_{t+u} / S_{t}) \) (using log rules).

    Now, if \( S_{t+u} / S_{t} \) does not depend on t (as per our assumption) then nor does \( log(S_{t+u} / S_{t} ) \).

    So, our increments, \( X_{t+u} - X_{t} \) are stationary. This means that the distribution of \( X_{t+u} - X_{t} \) only depends on the duration u, not at what point in time the increment starts, t. So, any two increments of length u would have the same distribution, regardless of when they started.

    I hope this helps

    Andy
     
  3. Kanishka

    Kanishka Active Member

    Thank you. This was very helpful to understand.
     

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