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ch 3 life tables

Because using AM92, select age for 48 with 2 year select duration is age 46
 
Hi Saksham.
See, there are two things- select mortality and ultimate mortality.
In the AM 92 table, select period is 2 years. (we denote select period by s). Which means, for duration ≥2, the select mortality will be same as ultimate mortality.
( [x] is denoted for select and x is for ultimate ).

Eg. L[46]+1 ≠ L47 (since duration is less than 2).
But L[46]+2 = L48 (since select mortaility is same as ultimate now for s≥2).

Notice that on page26, there is a condition for the formula you are talking about. That is used for t=s-1, .....,1,0.
Means if select period is 2, we can only use this formula for t= 1,0. And for rest,
L[x]+s = Lx+s.

In the example of page27, select period is given 2. (See in the given table the mortality is different for durations 0 and 1 and then same for duration≥2).
Thats why L[46]+2 = L48

Hope this helps!
 
Bharti Singla said:
Hi Saksham.
See, there are two things- select mortality and ultimate mortality.
In the AM 92 table, select period is 2 years. (we denote select period by s). Which means, for duration ≥2, the select mortality will be same as ultimate mortality.
( [x] is denoted for select and x is for ultimate ).

Eg. L[46]+1 ≠ L47 (since duration is less than 2).
But L[46]+2 = L48 (since select mortaility is same as ultimate now for s≥2).

Notice that on page26, there is a condition for the formula you are talking about. That is used for t=s-1, .....,1,0.
Means if select period is 2, we can only use this formula for t= 1,0. And for rest,
L[x]+s = Lx+s.

In the example of page27, select period is given 2. (See in the given table the mortality is different for durations 0 and 1 and then same for duration≥2).
Thats why L[46]+2 = L48

Hope this helps!
Click to expand...
Thankyou very much :)
 
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