D
DonnieDarkest
Member
Hi,
I'm having trouble understanding the derivation of the partial differential equations in Chapter 12 Competing Risks. In the simple example, a transition is possible from A to R, from R to D and from A to D.
I think I understand why we need v=0 (tranition intensity from R to D) in order for (aq)d = pAD ...otherwise pAD would also include the possibility of a transition from A to R then from R to D, with v=0 this is now not possible.
When this logic is extented, why do we also need to set v=0 in order for (aq)r = pAR ?
Is (aq)r = pAR by definition regardless of what v is?
Thanks!
I'm having trouble understanding the derivation of the partial differential equations in Chapter 12 Competing Risks. In the simple example, a transition is possible from A to R, from R to D and from A to D.
I think I understand why we need v=0 (tranition intensity from R to D) in order for (aq)d = pAD ...otherwise pAD would also include the possibility of a transition from A to R then from R to D, with v=0 this is now not possible.
When this logic is extented, why do we also need to set v=0 in order for (aq)r = pAR ?
Is (aq)r = pAR by definition regardless of what v is?
Thanks!