Black Scholes

Discussion in 'CT8' started by justine otieno, Mar 6, 2013.

  1. Hi,

    What probabilities do d1 and d2 represent in the Black Scholes formulae?
     
  2. Oxymoron

    Oxymoron Ton up Member

    If you integrate (St - K) from k to infinity, assuming
    St ~ LogNor(Mu = Ln(S0 + [r-s^2/2)*(T-t)], sigma = (s^2)*(T-t)],
    using the formula from page 18 of the actuarial tables you will get a solution equal to the Black-Scholes formula.
     
    Last edited: Mar 6, 2013
  3. So d2=Pr[St>K]? what about d1?
     
  4. Edwin

    Edwin Member

    N(d1) = P[S>K] when the payoff of a vanilla European Call Option is a share, an effect of Oxymoron's approach above.

    so asset or nothing call has form ct = So*N(d1)

    N(d2) = P[S>K] when the payoff of a vanilla European Call Option is cash.

    so cash or nothing call has form ct = Qexp(-rT)*N(d2)

    Hence German Kohlhagen form for a vanilla European call paying S-K (Share minus cash) has form;-

    ct = sN(d1) - kexp(-rT)N(d2)

    **d1 and d2 alone aren't probabilities, they are numbers.
     
    Last edited by a moderator: Mar 9, 2013
  5. Graham Aylott

    Graham Aylott Member

    Phi(d2) = risk-neutral probability that ST > K.

    This has proved a really useful result in answering a number of CT8 exams questions. :)

    Phi(d1) = Phi(d2) x Present value of (ST | ST > K) x (1/St)

    This doesn't have a nice and neat interpretation as a risk-neutral probability and to date hasn't been of relevance to any CT8 exam questions.
     
  6. Edwin

    Edwin Member

    Graham Aylott what do u think of my definition of N(d1) above, assuming you are familiar with Oxymoron's approach I.e N(d1) results when you integrate s*f(s) from K to infinity?
     
  7. Graham Aylott

    Graham Aylott Member

    The whole of the left-hand term in the Black-Scholes formula represents the expected present value of a payment of ST if given ST > K, ie:

    EPV[ST | ST> K] = St*Phi(d1).

    However, as risk-neutral prob[ST > K] = Phi(d2), it must be the case that:

    PV[ST | ST> K] * Phi(d2) = St*Phi(d1)

    So:

    Phi(d1) = PV[ST | ST> K] * Phi(d2) / St

    ie Phi(d1) doesn't have an interpretation as a risk-neutral probability. This is because it also incorporates the (random) growth in St.

    As far as the exam is concerned, the important things are to:

    (1) be able to derive the pricing formulae for specific derivatives, using the general risk-neutral ("5-step") pricing formula and the formula on p18 in the Tables

    (2) remember that Phi(d2) is the risk-neutral prob that ST > K, which can also be useful for valuing derivatives (and 1 - Phi(d2) is the risk-neutral prob of default in the Merton model.)
     

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